5(sin^2)x+7cosx+1=0

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Solution for 5(sin^2)x+7cosx+1=0 equation: 


Simplifying
5(sin2) * x + 7cosx + 1 = 0

Multiply in2s * x
5in2sx + 7cosx + 1 = 0

Reorder the terms:
1 + 7cosx + 5in2sx = 0

Solving
1 + 7cosx + 5in2sx = 0

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-1' to each side of the equation.
1 + 7cosx + -1 + 5in2sx = 0 + -1

Reorder the terms:
1 + -1 + 7cosx + 5in2sx = 0 + -1

Combine like terms: 1 + -1 = 0
0 + 7cosx + 5in2sx = 0 + -1
7cosx + 5in2sx = 0 + -1

Combine like terms: 0 + -1 = -1
7cosx + 5in2sx = -1

Add '-5in2sx' to each side of the equation.
7cosx + 5in2sx + -5in2sx = -1 + -5in2sx

Combine like terms: 5in2sx + -5in2sx = 0
7cosx + 0 = -1 + -5in2sx
7cosx = -1 + -5in2sx

Divide each side by '7osx'.
c = -0.1428571429o-1s-1x-1 + -0.7142857143in2o-1

Simplifying
c = -0.1428571429o-1s-1x-1 + -0.7142857143in2o-1

Reorder the terms:
c = -0.7142857143in2o-1 + -0.1428571429o-1s-1x-1

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